3 mangoes and 4 apples costs 85. 5 apples and 6 peaches costs 122. 6 mangoes and 2 peaches costs 114. what is the combined price of 1 apple, 1 peach and 1 mango?
a)37
b)39
c)35
d)36

• ... from the question
  3m+4a=85---->1
  5a+6p=122---->2
  6m+2p=114----->3
  solve 1 and 3
  we get 8a-2p=56.let it be 4th eq.
  now solve 4 and 2.
  29a=290
  a=10.from 4,by substituting a,we get p=12.
  substitute a,p in eq3.we get m=15
  now a+b+c=10+12+15=37.
  
• 10 years agoHelpfull: Yes(11) No(0)
• 3m+4a=85...(i)
  5a+6p=122....(ii)
  6m+2p=114....(iii)
  after solving (i) & (ii),we get the eqn in terms of m & p i.e
  15m-24p=-63....(iv)
  now, we solve eqn(iii) & eqn(iv),we get
  m=15,a=10,p=12 then total=15+10+12=37
  
• 10 years agoHelpfull: Yes(3) No(0)
• 3m+4a=85----->1
  5a+6p=122----->2
  6m +2p=114---->3
  solve 1 and 3 we get equation in a and p
  then solve that equation with 2
  finally you get a=10 p=12 m=15
  so ans is 37
• 10 years agoHelpfull: Yes(0) No(0)
• 3m+4a=85----(1) eqn
  5a+6p=122----(2)eqn
  6m+2p=114-----(3)eqn
  solve 1 and 3
  we get 8a-2p=56.let it be 4th eqn.
  now solve 4 and 2.
  29a=290
  a=10.from 4,by substituting a,we get p=12.
  substitute a,p in eqn3.we get m=15
  now a+b+c=10+12+15=37
• 10 years agoHelpfull: Yes(0) No(0)
• 3m+4a+0p=85...(1)
  0m+5a+6p=122..(2)
  6m+0a+2p=114..(3)
  solving eqn 1,2&3 we get value of m=15,a=10,p=12 there for 15+10+12=37
  
• 10 years agoHelpfull: Yes(0) No(0)