15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take, if 3 women do as much work as 2 men ?

• Time taken by 1 man by working 1 hr a day= 21*8*15 days
  Time taken by 2 men by working 1 hr a day= 21*8*15/2=21*4*15
  So time taken by 3 women by working 1 hr a day= 21*4*15
  So Time taken by 1 woman by working 1 hr a day=21*4*15*3
  So Time taken by 21 women by working 6 hr a day=21*4*15*3/6*21=30 days
• 10 years agoHelpfull: Yes(44) No(2)
• 15*21*8=2520 man hrs
  3w=2men,
  1 w=2/3 men,
  6d*21*2/3=2520
  d=30days
  
• 10 years agoHelpfull: Yes(31) No(2)
• 2 men = 3 women;
  21(3*7) women = 2*7 = 14 men
  15*21*8 = 6*d*14;
  d = 30 days.
• 10 years agoHelpfull: Yes(12) No(0)
• 2m=3wm So, 15m=45/2wm
  
  w1=w2
  wm1d1h1=wm2d2h2
  45/2*21*8= 21*d2*6
  d2=30 days
• 10 years agoHelpfull: Yes(6) No(0)
• Condition : 3 women do as much work as 2 men
  
  3(women) = 2(men)
  
  Given 21(women) = 7*3(women)
  
  According to condition : 7 * 2 = 14 (men)
  
  formula D = M*D*H/M*H
  
  so Days = 15*21*8/14*6 = 30 Days
• 9 years agoHelpfull: Yes(1) No(1)
• use MDH M =man D= days H = time /hours
  
  15*21*8=x*14*6
  
  x=15*21*8/14*6
  
  X=30
• 9 years agoHelpfull: Yes(0) No(0)
• M1*D1*H1/ W = M2*D2*H2/W M=MAN D=DAY H= HOUR W=WORK
  
  15*21*8/W= M2*D2*6/W (HERE first need to find M2)
  
  availabel woman =21
  
  3 woman work done= 2 men work done
  so in the 21 woman, 7 group of 3 woman is there(as 3*7=21) (3w, 3w, 3w..........7 times= 21 woman)
  
  indirect way 2*7= 14 men
  so 21 woman strength =14 men strength
  
  15*21*8/w =14*d2*6/w
  
  D2= 30 DAYS...
  
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• 30
  21women=14 men
  now, men*days*hours=constant(same work)
  15*21*8=14*6*x
  x=30
• 9 years agoHelpfull: Yes(0) No(0)