highest power of the 2 in the following series 1!+2!+3!---------------+600!
A.1
B.496
C.128
D.192

• highest power of 2 is zero
  because adding the series 2!+3!+.......+600! we get even number
  and when we add 1! to that even number we get odd number.
• 10 years agoHelpfull: Yes(37) No(7)
• 128 is the right ans.
  
• 10 years agoHelpfull: Yes(3) No(2)
• POWER OF 2 IS ZERO
• 10 years agoHelpfull: Yes(2) No(0)
• highest power of 2 is zero
  
• 10 years agoHelpfull: Yes(1) No(0)
• 0
  as the num is odd
• 10 years agoHelpfull: Yes(1) No(0)
• every element in above series having at least one 2 as a factor..except first element....summation of above series will be odd so there is not any degree of 2 as factor of that summation..so.. power is 0
• 10 years agoHelpfull: Yes(1) No(0)
• @chaman will u pls elaborate
• 10 years agoHelpfull: Yes(0) No(0)
• option B is correct
  
• 10 years agoHelpfull: Yes(0) No(1)
• highest power of 2 is zero
• 10 years agoHelpfull: Yes(0) No(0)
• Option B is correct
• 10 years agoHelpfull: Yes(0) No(2)
• shreya how
• 10 years agoHelpfull: Yes(0) No(0)
• ans is 1,it is asking highest power,
• 9 years agoHelpfull: Yes(0) No(0)
• option B is correct
  as take Lcm of all 4 options 498 has max 2 so it's the ans
• 9 years agoHelpfull: Yes(0) No(0)
• Please suggest some solution for this probelm.
• 9 years agoHelpfull: Yes(0) No(0)
• @Pratik Mishra i understand what u are trying to imply but what is the answer which option to choose from the above then ????
• 9 years agoHelpfull: Yes(0) No(0)
• Here the 1st term 1! is an odd nos and each of the remaining terms from 2! , 3! to.....600! is even. So the overall sum will be odd and hence not divisible by 2. So the power of 2 will be 0
• 7 years agoHelpfull: Yes(0) No(0)