The ages of two friends is in the ratio of 6:5.If the sum of their ages is 66. Then after how many years will the ratio become 7:6?

• the ratio of ages is 6:5 or we can say 6x and 5x
  so , 6x+5x=66 (sum)
  x=6
  the ages are 6*6=36 and 6*5=30
  let the years after which ratio will become 7:6 be y
  36+y/30+y=7/6
  the value of y will be 6
  
• 10 years agoHelpfull: Yes(13) No(0)
• 6 yrs
  6x,5x
  11x=66
  x=6
  now age =36 and 30
  let after y yr ratio will b 7:6
  36+y/30+y=7/6
  y=6
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• let age of 1st frnd = x
  then age of 2nd frnd will be 66-x
  equate
  x/(66-x) = 6/5
  solving age of 1 frnd is 36 and other frnd is 30
  
  now take (36+y) / (30+y) = 7/6
  on solving we get
  y=6
  ans after 6 yrs age will be in ratio 7:6
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• THE BANS WILL BE AFTER 6 YEARS
  BCZ THEIR AGES ARE 36 AND 30 WHICH ARE INB RATIO OF 5:6
  SO AFTER 6 YEAR IT WILL BE 7:6
  
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• ratio =5:6
  required ratio=7:6,
  that means the age should be divisible by 6+7=13,
  sum of there age is 66,the minimum value need to add for divisible by 13 is 12,
  66+12=78 which 6 times of 13
  12 is for both of them ,so 6 year is need to getthat ratio
  
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• let the present ages be 6x and 5x respectively.
  => 6x+5x= 11x= 66
  => x=6
  i.e 36 and 30 respectively.
  since 1 unit = 6, and nr and dr increase by 1 unit each, hence after 6 years their ratio will be 36+6/30+6 = 42/36 i.e, 7/6
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• let the age of A be x yrs.
  then age of B be( 66-x) yrs. since sum of age of A and B is 66.
  A/Q,
  x/(66-x)=6/5
  => x=36
  so Age of A is 36 yrs. and B is 30 yrs
  now let after x yrs ratio of age of A and B will be 7:6
  so
  (36+x)/(30+x)=7/6
  x=6.
  
  so after 6 years ratio of Age of A and B will be 7:6
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• after 6 year
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• let hcf be x,so, 6x+5x=66
  or, x=6
  so,the age is 36 & 30.Now,the ratio will become 7:6,so, 42 & 36.So, after 6 years the ratio will be 7:6.
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• After 6 years
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