ABCD is a horizontal rectangular field with AB = 50 m and BC = 27 m. AT is a vertical mast, the angle of elevation from B to T is 45o, calculate the distance from C to T.

• Try to draw the figure first and you will the solution described below clearly
  As mast is AT
  therefore tan45=AT/AB
  AT=AB,, i.e, AT=50m
  now TD=AT+AD=77 m
  and now if we see the triangle TDC then
  by pythagoras theorm CT(hypotenuse)=Sqrt(77^2+50^2)
  which is 91.08 m(approx)
• 10 years agoHelpfull: Yes(25) No(11)
• since from b the angle is 45...so tan45=AT/AB... and thats how we get AB=AT. now find AC which is 3229^1/2 and finally u can calculate CT which is 50^2 + 56.82^2 so finally you will get 75.68m...
• 10 years agoHelpfull: Yes(19) No(2)
• Answer is = 75.69
• 9 years agoHelpfull: Yes(8) No(0)
• Tan(45o)=(AB/AT)=(50/(27+DT))
  DT=23
  CT=sqrt(DC^2+DT^2)
  CT=55.036
• 10 years agoHelpfull: Yes(7) No(5)
• as ATB is Right angle triangle
  AT = TAN 45 * AB = 50m
  AC=sqrt of (AB^2+BC^2)
  = sqrt of(50^2 + 27^2)
  =56.82
  
  NOW triangle ACT IS a right angle triangle
  
  so CT = sqrt of (AT^2+AC^2)
  = sqrt of(50^2 + 56.82^2)
  =75.68
  
  
• 8 years agoHelpfull: Yes(5) No(0)
• square root of((50+27)^2+50^2)=91.80 since acc to ques cdt become right angle tringle
  
• 10 years agoHelpfull: Yes(2) No(1)
• angle of elevation from b to t is=45,so AB=AT=50.let AT=AD+DT . Hence AD=27 nd DT=50-27=23.
  in triangle TDC, DT=23,DC=50 so CT=sqrt of (DT^2+DC^2).hence CT=52.something.
• 10 years agoHelpfull: Yes(1) No(4)
• 27
  bct is right angle traingle
  so, ct/bt=tan 45o
  therefore, ct = 27
• 10 years agoHelpfull: Yes(1) No(6)
• 50,since c to d is same
• 10 years agoHelpfull: Yes(1) No(0)
• CT^2=50^2+23^2
• 10 years agoHelpfull: Yes(1) No(2)
• tan45=(AD+DT)/AB
  DT=13
  sin45=13/CT
  CT=13*sqrt(2)=18.38
• 10 years agoHelpfull: Yes(1) No(1)
• How can the the answer be 50+. because the given length is just 50. I think the answer is 27.
• 9 years agoHelpfull: Yes(1) No(0)
• ans is 91.80
• 8 years agoHelpfull: Yes(1) No(0)
• ct/bt=tan 45o
  therefore, ct = 27
• 10 years agoHelpfull: Yes(0) No(0)
• Since angle atb=45 then tan45=AB/AT
  SO AT=50m
  From triangle ATC WE CAN GET TC =56•82m
• 10 years agoHelpfull: Yes(0) No(0)
• 27 is the ans
  
  coz of right angle triangle
• 10 years agoHelpfull: Yes(0) No(0)
• √(23^2 + 50^2). Ans= 55
• 9 years agoHelpfull: Yes(0) No(0)
• Ans:27
  50
  A___________________B=45 degrees.Then BC = CT = 27m
  | /|
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  | / | 27
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  |_______ /________|
  D T C
  
• 9 years agoHelpfull: Yes(0) No(1)
• Ans 70.71m
  
  
  tan45=AT/AB
  AB=AT=50
  Since rectangular field therefore AB=DC =50
  CT =sqrt(50,50)
  which is equal to 70.71m
  
• 9 years agoHelpfull: Yes(0) No(1)
• (AC)^2 = (AB)^2 +(BC)^2
  AC=56.82
  tan45=AT/AB => AT=50(1)
  =>AT=50
  CT=CA+AT
  = 56.82+50
  =106.82
• 8 years agoHelpfull: Yes(0) No(1)