In how many ways a team of 11 must be selected from 5 men and 11 women such that the

it has said not more dan 3 men( not exactly 3 men ),,,,,,,,so 0 men 11 women,1 man 10 women,2 men 9 women ,3men 11 women posbl
so ans will be
11c11+5c1*11c10+5c2*11c9+5c3*11c8
10 years agoHelpfull: Yes(10) No(1)
Number of ways are = 11C11+5C1×11C10+5C2×11C9+5C3×11C8 = 2256

ans ) 2256
10 years agoHelpfull: Yes(5) No(1)
(5c3*11c8) + (5c2*11c9) + (5c1*11c10)
10 years agoHelpfull: Yes(2) No(0)
11c11+11c10*5c1+11c9*5c2+11c8*5c3=2256
10 years agoHelpfull: Yes(1) No(0)
Yes, the answer i think is 2256 as 11C11+5C1×11C10+5C2×11C9+5C3×11C8 = 2256
10 years agoHelpfull: Yes(1) No(0)
11C11+5C1×11C10+5C2×11C9+5C3×11C8 = 2256, is the answer.
10 years agoHelpfull: Yes(1) No(0)
ans is 1650

Solution- 5c3 * 11c8
10 * 165
1650 Answer
10 years agoHelpfull: Yes(0) No(5)
Total 5 men and 11women =16 person
Not more than 3men - 5c3
Remaining 11-3= 8
Now 8 women out of 11 -= 11c8
5c3*11c8 = 1650
10 years agoHelpfull: Yes(0) No(4)
no of ways=5C3*11C8+5C2*11C9+5C1*11C10
=1320+550+55
=1925
10 years agoHelpfull: Yes(0) No(1)

In how many ways a team of 11 must be selected from 5 men and 11 women such that the team must comprise of not more than 3 men?