Simple question but big one on average age.sth like a, b, c weighted separately 1st a, b, c ,then a& b, then b &c then c & a at last abc, the last weight was 167,then what will be the average weight of the 7 reading?

• avg=A+B+C+(A+B)+(B+C)+(C+A)+(A+B+C)/7
  Now,4A+4B+4C/7
  =4(167)/7 (GIVEN ABC=167)
  =95.43 ANS
• 9 years agoHelpfull: Yes(14) No(2)