find the probability when y=x^4+4 is divisible by 5.
a.1/5
b. 2/5
c.1/9
d. 4/5

• ans will be d.) 4/5
  
  suppose x=0,1,2,3,4,5,6,7,8,9
  value of x=10(sample space or possibility)
  
  in which only x=0,5 is not divisible by 5
  
  these two condition is not divisible by 5
  
  so probability of divisible by 5= no of event (divisible by 5)/sample space(total possibility)
  p (x)= 8/10
  = 4/5
• 10 years agoHelpfull: Yes(18) No(2)
• 2/5
  as last digit of x^4 should be either 1 or 6 ( because a no is divisible by 5 if lat digit is 0 or 5)
  so the x values should be 1,2,3,4,6,7,8.9
  total 5 digit no is 90000 and total no divisible by 5 is about 36000 so
  probability=36000/90000=2/5
  
• 10 years agoHelpfull: Yes(4) No(6)
• it is also given that X is five digit no...then for divisibility of 5 it should be the last digit either 5 or 0,then we to find how many no are there having it unit digit 6 or 1,then 18000 are there having last digit loke this...then probablity=18000/90000=1/5 ans a.
• 10 years agoHelpfull: Yes(0) No(1)
• right answer please...
• 10 years agoHelpfull: Yes(0) No(1)
• 2/5 final ans
  
• 10 years agoHelpfull: Yes(0) No(1)
• answer : the five digit no. X will be divisible only when it has 5 "or" 0 in the one's position .. and the a five digit no. is possible when the one's position is 0, 1, 2, 3, 4 ,5 ,6 ,7 , 8, 9 ..i.e, in 10 ways ..but for divisibility from 5 there are 5 cases possible when in these digits are in one's position 1=> 1+4=5 , 3=>1+4=5,7=>1+4=5,9=>1+4=5
  So, 4/10 = 2/5 Answer
• 9 years agoHelpfull: Yes(0) No(0)