if x-10 y-5 z-2 1000 then what is the least value of x y z if x y z are

Answer:47
(x-10)(y-5)(z-2)=10^3
that means x-10=10
y-5=10
z-2=10
If we solve these three equations we can get x,y,z values as 20,15,12 respectively.Then
x+y+z must be 47.
10 years agoHelpfull: Yes(8) No(7)
Since we have to get least value,
x=0
y=-5
z=12
so x+y+z=7
10 years agoHelpfull: Yes(5) No(1)
1000=2^ 3*5^3
1000=(35-10)(13-5)(7-2)
then x+y+z= 35+13+7=55
10 years agoHelpfull: Yes(0) No(5)
1000= 10*10*10
or (20-10)(15-5) (12-2)= 1000
x=20 .y= 15,z=12 x+y+z= 47
10 years agoHelpfull: Yes(0) No(3)
(x-10)=-10
(y-5)=-5
(z-2)=20 then x=0,y=0,z=22.Therefore,x+y+z=22
10 years agoHelpfull: Yes(0) No(4)
Sneha paliwal @ what u will say if I show -983 as their sum.
X=-990, Y=4, Z=3
(-1000)(-1)(1)=1000.
Source : fb
10 years agoHelpfull: Yes(0) No(5)
1000 can be written in factored form as 4*25*10
so if (x-10)=4; x=14
if (y-5)= 25; y=30
if (z-2)=10; z=12
14+30+12=56
56 is the aanswer
10 years agoHelpfull: Yes(0) No(7)

if(x-10)(y-5)(z-2)=1000 then what is the least value of x+y+z? if x,y,z are all integer no.