Q. The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:

Option
A. 123
B. 127
C. 235
D. 305

• B. 127
  
  HCF of 1651 ( 1657-6) and 2032 (2037-5) is 127.
• 12 years agoHelpfull: Yes(27) No(5)
• 1657-6 and 2037-5 we get numbers as 1651,2032
  no find H.C.F of 1651 and 2032 we get 127 as answer
  Option:B
• 11 years agoHelpfull: Yes(7) No(2)
• 1657-6=1651
  2037-5=2032
  2037/1651= rem 381
  1651/381= rem 127
  381/127=rem0
  hence h.c.f= 127
• 9 years agoHelpfull: Yes(3) No(1)
• ans b
  1657-6=1651
  2037-5=2032
  h.c.f(1651,2032)=127
• 9 years agoHelpfull: Yes(0) No(0)
• 1657/127 leaves remainder 6, 2037/127 leaves remainder 5
• 7 years agoHelpfull: Yes(0) No(0)
• ans is 127
• 7 years agoHelpfull: Yes(0) No(0)
• 1657-6 and 2037-5 we get numbers as 1651,2032
  no find H.C.F of 1651 and 2032 we get 127 as answer
  Option:B.
• 7 years agoHelpfull: Yes(0) No(1)
• 127
  1657-6=1651
  2037-5=2032
  so the number should exactly divides the above two numbers
  
• 7 years agoHelpfull: Yes(0) No(0)