There are 8 digits and 5 alphabets.In how many ways can you form an alphanumeric word using 3 digits and 2 alphabets?

• 8C3*5C2*5!=67200
• 10 years agoHelpfull: Yes(32) No(5)
• Select 3 digits from 8 digits i. e., 8C3 ways
  And also select 2 alphabets from 5 alphabets i.e.,5C2 ways
  Now to form a alphanumeric word of 5 characters we have to arrange the 5 selected digits.
  So the answer is (8C3*5C2)*5!=43200
• 10 years agoHelpfull: Yes(31) No(25)
• 3 digits from 8 digits cn b done in 8C3 ways
  2 alphabets from 5 alphabets cn b done in 5C2 ways
  Now dis selected 5 characters cn b arranged in 5! ways
  So answer = (8C3*5C2)*5!=67200
  
• 10 years agoHelpfull: Yes(11) No(4)
• 8c3*5c2=56*10=560
• 10 years agoHelpfull: Yes(7) No(8)
• ans:
  8C3*5C2
• 10 years agoHelpfull: Yes(6) No(7)
• take any three no from 8 digits and 2 alphabets from 5 alphabets
  8C3*5C2=56*10=560
• 10 years agoHelpfull: Yes(2) No(3)
• the answer is (8C3*5C2)*5!
• 10 years agoHelpfull: Yes(2) No(1)
• ans is 560*5!=43200
  
• 10 years agoHelpfull: Yes(1) No(8)
• 560
  8p3*5p2=560
  
• 10 years agoHelpfull: Yes(1) No(2)
• 8C3*5C2*5!=67200
• 10 years agoHelpfull: Yes(1) No(2)
• 8C3*5C2 is the answwer
• 10 years agoHelpfull: Yes(1) No(3)
• 8c3=56
  5c2=10
  arrange the 5 ch in 5! ways=120
  =56*10*120
  =67200
• 6 years agoHelpfull: Yes(1) No(0)
• 8c3*5c2=360
• 10 years agoHelpfull: Yes(0) No(4)
• 8c3*5c2*5!=67320
• 10 years agoHelpfull: Yes(0) No(4)
• 8p5*5p3=448
• 10 years agoHelpfull: Yes(0) No(4)
• 8c3 * 5c2 * 5!=57600
• 10 years agoHelpfull: Yes(0) No(3)
• Buy her an hearing aid and propose her :-P
• 10 years agoHelpfull: Yes(0) No(0)
• (8c3*5c2)*5!=403200
• 10 years agoHelpfull: Yes(0) No(2)
• 8c3*5c2*5!=67200
• 6 years agoHelpfull: Yes(0) No(0)
• 8c3*5c2*5!=43200
• 6 years agoHelpfull: Yes(0) No(0)
• we use P&C
  5C2 * 8C3 * 5!=67200
• 4 years agoHelpfull: Yes(0) No(0)
• An alphanumeric word of 5 character
  Using 3 digits out of 8 digits=8C3=56
  and 2 alphabets out of 5 alphabets=5C2=10
  The 5 character can be arranged among then in 5! ways
  Therefore the total number of ways to form alphanumeric word =56*10*5!=67200
• 4 years agoHelpfull: Yes(0) No(0)
• It is a question of combination. So 8C3 digit and 5c2 for word.
  8C3 * 5C2 =560
• 4 years agoHelpfull: Yes(0) No(0)
• 8c3*5c2*12=6720
• 3 years agoHelpfull: Yes(0) No(0)