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Numerical Ability
Number System
For every positive integer n, form the number n / s(n), where s(n) is the sum of the digits of n in base 10. What is the minimum value of n/s(n) for 10 <= n <= 99.
a) 1.2
b) 3.45
c) 1.9
d) 2
Read Solution (Total 6)
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- possibility to sum of digits 10
i.e
(1.9),(2,8),(3,7),(4,6),(5,5)
we get s/s()n are 1.9,2.8,3.7,4.6,5.5
so the minimum possibility of s/s(n)=19/10=1.9 - 10 years agoHelpfull: Yes(13) No(1)
- 10x+y/x+y
let x=1 and y = 9
19/10=1.9 - 10 years agoHelpfull: Yes(8) No(1)
- 1.9
19/10 is smallest - 10 years agoHelpfull: Yes(5) No(3)
- As n is a two digit no starting from 10,let it be 10x+y.and s(n) be x+y
for n=10here x=1 and y=0 ,n/s(n)= (10+0)/(0+1)=10
similarly for n=11,n/s(n)= (10+1)/(1+1)=5.5
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it will give the lowest value for x=1 and y=9 so n/s(n)=(10+9)/(1+9)=1.9 - 10 years agoHelpfull: Yes(4) No(1)
- please clarify as simple as you can....
- 10 years agoHelpfull: Yes(1) No(0)
- 19/1+9=1.9
- 9 years agoHelpfull: Yes(0) No(0)
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