For every positive integer n, form the number n / s(n), where s(n) is the sum of the digits of n in base 10. What is the minimum value of n/s(n) for 10 <= n <= 99.

a) 1.2
b) 3.45
c) 1.9
d) 2

• possibility to sum of digits 10
  i.e
  (1.9),(2,8),(3,7),(4,6),(5,5)
  we get s/s()n are 1.9,2.8,3.7,4.6,5.5
  so the minimum possibility of s/s(n)=19/10=1.9
• 9 years agoHelpfull: Yes(13) No(1)
• 10x+y/x+y
  let x=1 and y = 9
  19/10=1.9
• 9 years agoHelpfull: Yes(8) No(1)
• 1.9
  19/10 is smallest
• 9 years agoHelpfull: Yes(5) No(3)
• As n is a two digit no starting from 10,let it be 10x+y.and s(n) be x+y
  for n=10here x=1 and y=0 ,n/s(n)= (10+0)/(0+1)=10
  similarly for n=11,n/s(n)= (10+1)/(1+1)=5.5
  .
  .
  it will give the lowest value for x=1 and y=9 so n/s(n)=(10+9)/(1+9)=1.9
• 9 years agoHelpfull: Yes(4) No(1)
• please clarify as simple as you can....
• 9 years agoHelpfull: Yes(1) No(0)
• 19/1+9=1.9
• 9 years agoHelpfull: Yes(0) No(0)