how many number x (x being an integer) with 10<=x<=99 are 18 more than sum of their digits?
a)12
B)9
C)18
10 ?

• Let the no. be 10y+z.
  then,
  10y+z= y+z+18
  => Y=2
  So the no. are 20, 21, 22, 23, 24, 25, 26, 27, 28, 29. Total nos. 10
• 9 years agoHelpfull: Yes(24) No(2)
• Let ab be the number
  ab=18+(a+b)
  10*a+b=18+(a+b)
  =>a=2,b=any number(0 to 9)
  20,21,22,-----29 are the number so x=10
  so Answer is 10
• 9 years agoHelpfull: Yes(19) No(4)
• Let the no. be 10X+Y
  then,
  10X+Y= X+Y+18
  => X=2
  So the no. are 20, 21, 22, 23, 24, 25, 26, 27, 28, 29. Total nos. 10
• 9 years agoHelpfull: Yes(2) No(0)
• 9
  let the no be 10x+y
  10x+y=x+y+18
  solving we get
  x=2
  therefore all no starting with two
• 9 years agoHelpfull: Yes(0) No(2)
• lets number is 10p+q,
  hence,
  10p+q=x+y+18(more)
  =>p=2,and q(0 to 9), put the value
  so the no obtain are 20,21,22,.............29.so total possible number or x=10
• 9 years agoHelpfull: Yes(0) No(1)