sum of digits of product (16^100)*(125*135) is
a.2 b.5 c.3 d.8

• The above equation can be simplified as
  ((2^400)*(5^405))
  ((2^400)*(5^400)*(5^5))
  ((2*5)^400)*(5^5))
  ((10^400)*(5^5))
  as we know that 10^n= 10000......
  so ((1000....)*(3125))
  we get 312500000.....
  ans=3+1+2+5+0+0+0..... =11
• 10 years agoHelpfull: Yes(27) No(2)
• (2^400)*(5^405)
  (2*5)^400*5^5
  (10)^400*3125
  31250000.....
  so the answer would be
  3+1+2+5=11=1+1=2
  Answer is option a)2
• 10 years agoHelpfull: Yes(11) No(10)
• @ Pooja
  125= 5^3
  so (5^3)^135=5^405
  hope u got me..
• 10 years agoHelpfull: Yes(3) No(3)
• Sum of digits should be 9, i think ans is wrong.
• 10 years agoHelpfull: Yes(2) No(7)
• how it is 5^405 plz explain
  
• 10 years agoHelpfull: Yes(2) No(1)
• 16^100=unit digit 6
  125^135=unit digit 5
  5*6=30
  ans=3+0=3
• 10 years agoHelpfull: Yes(2) No(4)
• ans will be 11
• 10 years agoHelpfull: Yes(1) No(0)
• those who submitted the solution using 5^405, the question is 125*135, not 125^135..... so is the question wrong, or you people did not notice??
• 9 years agoHelpfull: Yes(1) No(0)
• I also have the same question..how is it simplified as 5^405...?
• 10 years agoHelpfull: Yes(0) No(1)
• ans will be 11
  
• 10 years agoHelpfull: Yes(0) No(1)