The difference between a three-digit number and the number formed by reversing its digits is not a multiple of??

• if digits of no. be xyz then
  
  100x + 10y + z - (100z + 10y + x) = 99*(x-z)
  i.e multiple of 99.
  
• 9 years agoHelpfull: Yes(13) No(1)
• Ans is 7
  I have few things to support my answer
  
  1.987-789=198. divisible by1,2,3,6 and 9
  2.991-199=792. Divisible by 4,8
  3.540-045=495. Divisible by 5.
• 9 years agoHelpfull: Yes(2) No(4)
• it must be multiple of 3
• 9 years agoHelpfull: Yes(0) No(2)
• it must be a multiple of 9.
• 9 years agoHelpfull: Yes(0) No(3)
• suppose- u take 561 and on reversing its digit the no is 156 . so difference is 561-156= 405 which clearly is divisible by 3 . like this for any three digit no you will get an answer which is divisible by 3. so it is a multiple of 3 and not a multiple of 9
• 9 years agoHelpfull: Yes(0) No(4)
• but Mr. Sourav Sarkar if u take 963,then the reverse will b 369 and there difference is 594 which is divisible by 9 ,so how the answer be 9?
• 9 years agoHelpfull: Yes(0) No(0)
• @ rakesh why u take 99*(x-z) pls reply
  
• 9 years agoHelpfull: Yes(0) No(0)
• ohk i got...
  
• 9 years agoHelpfull: Yes(0) No(0)
• Fdz read the question once and they have asked which is not a multiple of.....
• 9 years agoHelpfull: Yes(0) No(3)