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What is the unit digit of 2^(3^456789)
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- we need to find last two digit of 3^456789
3^456789 = (81)^114197 * 3 = ---61*03 = -----83 [unit is 1, tenth = 8*7]
2^(3^456789) = 2^(-------83) => unit digit = 2^3 = 8 - 10 years agoHelpfull: Yes(17) No(2)
- According to the cyclicity of 3 ( 3,9,7,1)....unit digit of 3^456789=3
And then 2^3= 8....!!! soo According to me unit digit will be 8...!!! Ans..
- 10 years agoHelpfull: Yes(12) No(8)
- sol:-
we have 2^3^456789
so first solve 2^3 i.e. 8.
now 8^456789
since 456789 is in the form of 4n+1
we write it as 4*114197+1
and by formula if no ending with 8 have power in the form of 4n+1 then its unit digit is 8.
hence ans is 8 - 10 years agoHelpfull: Yes(7) No(2)
- 3^456789=(81)^114197*3=61*3=83
a number is divided by 4 if last two digits divided by 4
83=80+3=4*20+3=4n+3=8 so answer is 8 - 10 years agoHelpfull: Yes(3) No(2)
- 3^9=3
2^3=8 - 10 years agoHelpfull: Yes(1) No(0)
- Answer-8 will be its unit digit
- 10 years agoHelpfull: Yes(1) No(1)
- Answer-8 will be its unit digit
- 10 years agoHelpfull: Yes(1) No(0)
- Answer-8 will be its unit digit
- 10 years agoHelpfull: Yes(1) No(1)
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