What is the unit digit of 2^(3^456789)

• we need to find last two digit of 3^456789
  3^456789 = (81)^114197 * 3 = ---61*03 = -----83 [unit is 1, tenth = 8*7]
  
  2^(3^456789) = 2^(-------83) => unit digit = 2^3 = 8
• 9 years agoHelpfull: Yes(17) No(2)
• According to the cyclicity of 3 ( 3,9,7,1)....unit digit of 3^456789=3
  And then 2^3= 8....!!! soo According to me unit digit will be 8...!!! Ans..
  
• 9 years agoHelpfull: Yes(12) No(8)
• sol:-
  we have 2^3^456789
  so first solve 2^3 i.e. 8.
  now 8^456789
  since 456789 is in the form of 4n+1
  we write it as 4*114197+1
  and by formula if no ending with 8 have power in the form of 4n+1 then its unit digit is 8.
  hence ans is 8
• 9 years agoHelpfull: Yes(7) No(2)
• 3^456789=(81)^114197*3=61*3=83
  a number is divided by 4 if last two digits divided by 4
  83=80+3=4*20+3=4n+3=8 so answer is 8
• 9 years agoHelpfull: Yes(3) No(2)
• 3^9=3
  2^3=8
• 9 years agoHelpfull: Yes(1) No(0)
• Answer-8 will be its unit digit
  
• 9 years agoHelpfull: Yes(1) No(1)
• Answer-8 will be its unit digit
  
• 9 years agoHelpfull: Yes(1) No(0)
• Answer-8 will be its unit digit
  
• 9 years agoHelpfull: Yes(1) No(1)