What is the average speed of a cyclist who covers first, second and third km at 20, 16 and 12 km/hr respectively (in km/hr)?

• ans- 15.32
  avg speed= 3*x*y*z/(x*y+y*z+z*x)
  where x,y and z are 20,16 and 12 respectively
  so,
  3*20*16*12/752 =15.319 i.e 15.32(approx)
• 10 years agoHelpfull: Yes(3) No(0)
• Ans:15.319 km/hr
  Take time as constant
  D/S=T
  Let x is the avg speed
  
  (1/20)+(1/16)+(1/12)=3/x
  
  47/240 = 3/x
  
  x=15.3191489 km/hr
• 10 years agoHelpfull: Yes(0) No(0)
• Let, x, y and z be 20, 16 and 12 respectively
  So the average speed of x, y and z will be,
  = 3*x*y*z/(x*y+y*z+z*x)
  by, putting the values of x, y and z, the average speed becomes = 15.319 i.e = 15.32approx(answer)
• 10 years agoHelpfull: Yes(0) No(0)
• ans is 51.32km/hr
  since... 20km ------> 60 min==> 1km -> 60/20
  16km----------> 60min--> 1km -> 60/16
  12km ----------> 60min--> 1km -> 60/12
  60(1/20+1/16+1/12) = 11.75 min
  for 11.75 min it covers 3km
  for 60 in it covers = 15.31km
• 10 years agoHelpfull: Yes(0) No(0)