Paul started from home with his bicycle travelling 6 km/hr at 12:00 pm and John started at 13:30 travelling 9 km/hr. At what time John will be 3 km ahead of Paul?

• Paul moves 9km in 12-13:30
  so, john will cover this distance of 9km at 2:30pm
  john and paul will cover equal distance at 4:30pm
  john covers 9km in 1hr and paul cover 6km in 1hr
  so by this after 1hr i.e at 5:30 john will be 3km ahead of paul
  becoz 9-6=3
  Ans is 5:30pm
• 9 years agoHelpfull: Yes(24) No(8)
• distance covered by paul in 1.5 hours= 6*1.5=9km
  relative speed 9-6=3km/hr
  total dis coverde by john is 9+3= 12km
  so time=12/3=4hrs
  17.30 ahead of paul
• 9 years agoHelpfull: Yes(18) No(0)
• at 13.30 hr Paul travels 9km
  let in x hr john will be 3km ahead
  then
  9x-(6x+9)=3
  x=4
  so at 13.30+4=17.30 john will be 3hr ahead from Paul
  
• 9 years agoHelpfull: Yes(17) No(0)
• 19:30 ans
  
• 9 years agoHelpfull: Yes(1) No(4)
• Ans is 15:30
  
• 9 years agoHelpfull: Yes(1) No(1)
• paul cover 1.5*6=9km
  but john is 3 km ahead of paul
  therefore
  total distance is 12km
  relative speed is 3kmph
  =>12/3=4 hrs
  i.e 13:30+4=17:30
• 9 years agoHelpfull: Yes(1) No(0)
• 17:30 john will be 3km ahead
  
• 9 years agoHelpfull: Yes(0) No(0)
• total 4 digit number will be 4*7=42
  total 5 digit number up to 19000=1*9*10=90
  so total palindrom=132
• 9 years agoHelpfull: Yes(0) No(2)
• ans is 19:30
  as at 18:30 they will be at same location and after 1hr john will be 3km ahead of paul...
• 9 years agoHelpfull: Yes(0) No(0)