Gate
Exam
Programming
Number of Address lines required for 1MB?
a.) 16
b.) 20
c.) 18
Read Solution (Total 3)
-
- If N is the number of address bus the it will offer 2^N byte memory(ROM).
for 1 MB N=20.. as 2^20=1024*1024 byte
- 10 years agoHelpfull: Yes(2) No(0)
- b
we required 20 bits because 1MB=2^20 bytes - 10 years agoHelpfull: Yes(0) No(0)
- the formula is 2^n where n is the no of address lines so 1 mb is 1024 which is n = 20
- 5 years agoHelpfull: Yes(0) No(0)
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