A number when successively divided by 1,5,8 leaves remainders 1,4,7resp. Find the respective remainders if the order of divisors be reversed.

• when a number is devided by 1 it does not leaves any remainder
• 9 years agoHelpfull: Yes(18) No(0)
• Let number be N
  N=K+1
  K=5L+4
  L=8M+7
  so K=5(8M+7)+4
  K=40M+39
  now N=40M+39+1
  =40M+40
  now put M=0 we get N=40 which is the least no.
  now order of divisor is reversed so it is 8 5 1
  first 40 is divided by 8 ,quotient 5 and remainder 0 .now 5 will be divided by 5 then quotient is 1 and remainder is 0 now 1 is divided by 1 so quotient is 1 and remainder will be 0
  so order of remainder will 0,0,0
  
• 9 years agoHelpfull: Yes(16) No(4)
• question is not correct
  when no is divided by 1 it leaves no remainder..
• 9 years agoHelpfull: Yes(5) No(0)
• 0 0 1 are the remainders.
  
  Three divisors are 1 5 8 and remainders are 7 4 1
  
  Find the dividend
  
  8*1+7=15, 15*5+4=79, 79*1+1=80. Dividend=80.
  
  Now divide 80 with 8 5 1 we get 0 0 1.
  
  ( the remainder must be 1 in the ending we cannot divide it by 1*2=2).
• 9 years agoHelpfull: Yes(2) No(0)
• l.c.m of 1,5,8=40 now subtract the common remainder i.e 40-1=39 so the no. is 39 when reversed is 93 .
  divided by 1,5,8 simultaneously gives 0,3 and 5 as a remainder.
  
• 9 years agoHelpfull: Yes(1) No(3)
• ans is 1,0,4
  
• 9 years agoHelpfull: Yes(0) No(3)
• can u plz explain this piyush...
  
• 9 years agoHelpfull: Yes(0) No(0)
• 1/x=y-1
  5/y-1=z-4
  8/z-4=1-7
  Z=8×1+7
  Y=5×z+4
  X=y+1=77
  Now 76÷(8,5,1)=4,4,0
• 9 years agoHelpfull: Yes(0) No(2)
• when a number is devided by 1 it does not leaves any remainder
  so there exit no such number
• 9 years agoHelpfull: Yes(0) No(0)
• if we reverse the divisors the remainders will be 0,0,0
  
• 9 years agoHelpfull: Yes(0) No(0)
• let N be a no.
  then a/c to questn,
  N=k+1
  k=5M+4
  M=8L+7
  solving these equatns we get, k=40L+40
  for L=0, N=40
  40/8 queotient=5 and remainder=0
  5/5 , queotient=1 and " =0
  1/1 , " =1 and " =0
  so the remainder after dividing the no is 0,0,0 respectively
• 9 years agoHelpfull: Yes(0) No(2)
• I think the question is wrong as if a number is divided by 1 it can never give a remainder, but nevertheless
  Here is the solution that i have:
  a number is first divided by 1 then by 5 then by 8, so
  8((5(1(x)+1)+4)+7)=40x+79
  
  Now all we need to do is the opposite so, 1 will be the outer most then 5 then 8,
  so,
  1(40x+79) //Divided by 1
  1(5(8x+25)+4) //Divided by 5
  1(5(8(x+3)+1)+4) //Divided by 8
  So remainders are 1,4,0
  If u think this is correct, mark as helpful
• 7 years agoHelpfull: Yes(0) No(2)