If F(n) = {x/x is a prime factor of n};

1. F(110) ∩ F(165)
(1) {5, 11} (2) {1, 5, 11} (3) {1, 2, 3, 5, 11} (4) {2, 3, 5, 11}

2. The least value of x when
F(x) ∪ F(15) = F(30)
(1) 2 (2) 0 (3) 1 (4) 30

• 
  
  110 = 2*5*11
  F(110) = {2,5,11}
  F(165) = {3,5,11}
  
  1. F(110) ∩ F(165) = {2,5,11} ∩ {3,5,11} = {5, 11}
  
  2. F(x) ∪ F(15) = F(30)
  F(15) = {3,5}
  F(30) = {2,3,5}
  so x must be 30.
• 10 years agoHelpfull: Yes(20) No(10)
• 1){5,11}
  2)min.value so it will be f(2) not f(30) #Rakesh
  
• 10 years agoHelpfull: Yes(20) No(0)
• 110=2*5*11
  so F(110)={2,5,11}
  F(165)={3,5,11}
  1.F(110) ∩ F(165) = {2,5,11} ∩ {3,5,11} = {5, 11}
  2.2. F(x) ∪ F(15) = F(30)
  F(15) = {3,5}
  F(30) = {2,3,5}
  so x=2.
  
• 10 years agoHelpfull: Yes(4) No(0)
• 110=2*5*11
  
  F(110)={2,5,11}
  F(165)={3,5,11}
  
  1.F(110) ∩ F(165) = {2,5,11} ∩ {3,5,11} = {5, 11}
  
  2.2. F(x) ∪ F(15) = F(30)
  F(15) = {3,5}
  F(30) = {2,3,5}
  
  so x=2.
  
• 10 years agoHelpfull: Yes(2) No(0)
• 110=11*5*2
  165=11*5*3
  from option prime factors={5,11}
  in 2
  
  
  x=30
• 10 years agoHelpfull: Yes(1) No(2)
• ans is {1,5,11}.
• 10 years agoHelpfull: Yes(1) No(0)
• (1) {5,11}
• 10 years agoHelpfull: Yes(0) No(0)
• Q1.Ans 2nd
  Q2.Ans 1st
• 10 years agoHelpfull: Yes(0) No(0)
• 110 = 2*5*11
  F(110) = {2,5,11}
  F(165) = {3,5,11}
  
  1. F(110) ∩ F(165) = {2,5,11} ∩ {3,5,11} = {5, 11}
  
  for the second part, the ans is option2 i.e. 0.
  how?
  F(15) = {3,5}
  F(30) = {2,3,5}
  so, we need just 2 (NOTE: this is union, NOT intersection).
  and,
  every whole no is a factor of zero.
  so,
  F(0) = {1,2,...)
  hence,
  F(0) ∪ F(15) = F(30)
• 9 years agoHelpfull: Yes(0) No(0)