if a bag contains 5 white, 3 green and 2 red balls . if three balls are drawn from the bag, what is the probability that two balls are green and one is red?

• let S be the sample space then
  n(s)=no of ways of drawing 3 balls out of 10
  =10c3=(10*9*8/3*2*1)=120
  
  n(E) no of ways of drawing 2 green and 1 red ball
  = 3c2*2c1
  =(3*2/2*1)*2
  =6
  
  p(E)=n(E)/n(S)
  =6/120
  =1/20
  
• 10 years agoHelpfull: Yes(0) No(0)