a(square)+b(square)+c(square)+3=2(a-b-c) then 2a-b+c= ?

• a^2 + b^2 + c^2 + 1+1+1 = 2(a-b-c)
  => (a^2-2a+1) + (b^2+2b+1) + (c^2+2c+1) = 0
  => (a-1)^2 + (b+1)^2 + (c+1)^2 = 0
  => a = 1, b = -1 , c = -1
  
  so, (2a-b+c) = 2+1-1 = 2
• 10 years agoHelpfull: Yes(4) No(0)
• (a-1)^2+(b+1)^2+(c+1)^2=0
  condition will be satisfied only when
  a=1 ,b=-1,c=-1
  so, value 2a-b+c=2*1+1-1=2
• 10 years agoHelpfull: Yes(0) No(0)
• a^2 + b^2 + c^2 + 1+1+1 = 2(a-b-c)
  => (a^2-2a+1) + (b^2+2b+1) + (c^2+2c+1) = 0
  => (a-1)^2 + (b+1)^2 + (c+1)^2 = 0
  => a = 1, b = -1 , c = -1
  so, (2a-b+c) = 2+1-1 = 2
• 10 years agoHelpfull: Yes(0) No(0)