11 March 2003 is Tuesday which contains 365 days in the year. Then what will be the day on 11 March 2004 which contain 366 days.

• Thursday
  10 march-wednesay 365 day
  feb 29 days
  so 366th days is 11 march 2004 so it is thurdsday
  
• 10 years agoHelpfull: Yes(10) No(2)
• from 11 March 2003 to 11 march 2004
  total days = 366
  so 366%7 = 2
  so on 11 march 2004 its Thursday
  if its not a leap year then 365%7 = 1
  then its Wednesday..
  
• 10 years agoHelpfull: Yes(3) No(1)
• 2004 is leap year of 366 days-odd days =366%4=2
  11 march,tues(2013)+2=11 march thurs(2014)
• 10 years agoHelpfull: Yes(2) No(1)
• we Know that 100 years contain 5 Odd days like that 200 yrs 3 odd days, adn 300 yrs only 1 odd day.
  1) Step 11 March 2003
  Divide 2003/400 and take remainder = 3 then we take 1 less year this will follow every questions
  means 2 days
  2) step 11 march how we find jan contain 31 days , Feb contain 28 ( non leap year) and march 11 days
  sum= 31+28+11=70 when we divide 70%7=0 then
  3) step = step1 + step 2=2+0=2
  we know 0 means sunday
  1 means monday
  2 means tuesday
  
  Like we solve 11 march 2004 2004/400=4 then we take 1 year less
  1 ) step - 3 value
  2) step -31+29+11=71 71%7=1
  3) step 3+1=4
  0 means sunday
  1 means monday
  2 tuesday
  3 wednesday
  4 thursday
  so ans is THursday
  
• 10 years agoHelpfull: Yes(2) No(0)
• Thursday.
  Non-Leap year 365 days : 1 Odd day
  Leap year 366 days : 2 odd days .
  2003 11 March Tuesday.
  2004 11 March Next day+ 1 day : Thurseday
• 10 years agoHelpfull: Yes(1) No(0)
• tuesday+2=thursday
  
• 10 years agoHelpfull: Yes(1) No(0)
• 2 odd days as leap year so thursday
  
• 10 years agoHelpfull: Yes(1) No(0)
• thrusday
  n=n+2
  
• 10 years agoHelpfull: Yes(0) No(0)
• 2004 is a leap year so 366 days
  366%7=2 odd days..
  so in 2003 if it was tuesday, den add 2+tuesday=thursday
  hence 11 march,2004 will be thursday
• 10 years agoHelpfull: Yes(0) No(0)