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Numerical Ability
LCM and HCF
A B C D all 4 have to cross a bridge. Bt dey can go only in pair. Dey also have to carry a lamp in each travel which z one side of the bridge. How much min tym will 4 of dem require to cross it if the speed of A is 1 min B is 2 min C is 7 min n D is 10 min?
Ans was 17.
Apart from solving cn plz any1 hlp me to find the right approach to the solution? Or does it just follows hit n trial method?
Read Solution (Total 2)
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- first A and B will travel together to cross the bridge ,so the total time taken will be highest of the two that is 2 min.
now a will come back with the candle it will take 1 min
so until now the total time is 2+1=3 min
now C and D will cross the bridge and the time will be 10 min
total time until now is 10+3=13 min
now b will come back and total time 13+2=15 min
A and b will cross the bridge 15+2=17 min - 10 years agoHelpfull: Yes(59) No(2)
- alwz sart with best two min people and send them
after wards maxm time taking
and at the end set it such that best people will go ........
as in example
a+b-------2min; A.......> 1min =3min in one trip;
c+d-------10min;B.......>2min = 10+2 min trip i.e 12 min;
now again A+b---------2min; Total trip time : 3+12+2=17 min :) - 10 years agoHelpfull: Yes(8) No(0)
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