32^32^32
--------------- =find the remainder?
9

• Ans is 4
  32/9 rem 5
  Solving (5^32)/9= (5^(4)(8) . 5^0)/9 =625/9 = rem 4
  Solving (4^32)/9= (4^(4)(8) .4^8)/9 = 256/9 =rem 4
  NOTE:n^0=n^4.
• 10 years agoHelpfull: Yes(0) No(0)
• Ans is 4
  32/9 rem 5
  Solving (5^32)/9= (5^(4)(8) . 5^0)/9 =625/9 = rem 4
  Solving (4^32)/9= (4^(4)(8) .4^8)/9 = 256/9 =rem 4
  NOTE:n^0=n^4.
• 10 years agoHelpfull: Yes(0) No(0)
• Ans is 4
  32/9 rem 5
  Solving (5^32)/9= (5^(4)(8) . 5^0)/9 =625/9 = rem 4
  Solving (4^32)/9= (4^(4)(8) .4^8)/9 = 256/9 =rem 4
  NOTE:n^0=n^4.
• 10 years agoHelpfull: Yes(0) No(0)
• Ans is 4
  32/9 rem 5
  Solving (5^32)/9= (5^(4)(8) . 5^0)/9 =625/9 = rem 4
  Solving (4^32)/9= (4^(4)(8) .4^8)/9 = 256/9 =rem 4
  NOTE:n^0=n^4.
• 10 years agoHelpfull: Yes(0) No(0)