A P R O C T ---------------------- P U R A R O J R R E C U -----------------------

A=4 P=3 R=2
O=5 C=6 T=7
10 years agoHelpfull: Yes(2) No(0)
here R+E gives no carry also R+R=A and R+E=A so here one carry is there,
so, if we take R=2 then A=4 and E=1.
now its easy to solve and answer is
4 3 2
5 6 7
-------
3 0 2 4
2 5 9 2
2 1 6 0
------------
2 4 4 9 4 4
10 years agoHelpfull: Yes(1) No(0)
here C*R=R....so 2 ways r there ...these are C=6,R=2,4,6 or u can take case 5 also...but no need of that
put C=6,R=2.....nw u can easily get value of A=4,
nw look here T*2= 4...obvio T=7
nw i dnt think it will create any problem for further steps....plz try urself ...it can be done easily
10 years agoHelpfull: Yes(0) No(0)

A P R
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P U R A
R O J R
R E C U
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R A A J A A
Kindly solve this as soon as possible plzzzzzz