I need solution of this cryptarithmetic with explanation

FYH
EWT
.......
ZETF
EKZZ
YZTX
........
YFYWEF

• 8 4 6
  5 7 3
  ----------------
  2 5 3 8
  5 9 2 2
  4 2 3 0
  ---------------------
  4 8 4 7 5 8
  ----------------------
• 9 years agoHelpfull: Yes(7) No(2)
• in this we can see dat E & Z is not generating any carry coz Y is as it is.
  the universal HINT is when t is multiplied with y the ans is T including possibility dat T and H multiplication can generate a carry and after dat (T*Y=T) whenever you come across like this just hit 3T*4Y+1=1(3T).
  maximum times it works so NOW you have T as 3 and Y as 4. now you have to put a value of y which when multiplied with T(i.e.3) should generate carry 1. there are only two left i.e. 3*6=18 and 3*5=15 . we can clearly see that value of H cannot be 5.so its obvious dat H is 6 . dats it question is Done
• 9 years agoHelpfull: Yes(6) No(0)
• is there any hint or not??
• 9 years agoHelpfull: Yes(0) No(1)
• no u have to take the hint from e+z =f and there will be no carry so start applying from there
• 9 years agoHelpfull: Yes(0) No(1)