A candidate must get 33% marks to pass. He gets 220 marks and fails by 11 marks. what is the number of maximum marks?

• Let the maximum marks be x.
  Now the candidate scores 220 and fails by 11 marks.
  Hence the passing marks will be (220+11)=231 marks.
  Thus form the equation-33%of x=231
  (33*x/100)=231
  x=(231*100)/33
  x=700.(ANS)
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• (220+11) = 33% of max. marks
  231 = (33* max. marks)/100
  max. marks = 700
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• since
  33% = 220+11
  1 = 231/33= 7
  100---- 7 *100= 700
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• 700 .
  220 = (x × 33/ 100 ) - 11
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