Remainder when 1212121212 up to 300 digits is divided by 99

Rahul, just check the remainder when we take 12 /99 that is 12 is two digit rem 12*1 then 1212 it is four digit , that is 12*2 so 12......(300dgt) then 12*150 hope you got it
10 years agoHelpfull: Yes(4) No(0)
RAKESH i dont understand why do you divide 12*150 by 99.we are already getting remainder 12*150 by dividing numbers with 99..so why do you again divide 12*150 by 99 in the last line????????? plz clarify ....it.........
10 years agoHelpfull: Yes(3) No(0)
121212121212.......(upto 300 digits) when divided by 3 gives
404040404040........(upto 299 digits), this when divided by 3 gives
134680134680134680..........13468,
then sum of odd place digits = 50*(1+4+8)=50*13
sum of even place digits =50*(3+6)=50*9
odd-even=50*4=200
200/11 we get remainder 2
therefore ans=2
10 years agoHelpfull: Yes(2) No(3)
12/99 rem=12
1212/99 rem=24=12*2
121212/99 rem=36=12*3
(12)(12).....150 tims/99 rem=12*150
(12*150)/99 rem=18
9 years agoHelpfull: Yes(2) No(0)
rahul, we again divide because 12*150 is greater than 99.
10 years agoHelpfull: Yes(1) No(0)
(12*150)/99 rem is 8
10 years agoHelpfull: Yes(1) No(2)
12(10^298+10^296+....10^2+1)%99
12(100^149+100^148....100+1)%99
12(1+1+1.............+1 150terms)%99
12(150)%99
(12*51)%99
612%99
18 ans
9 years agoHelpfull: Yes(1) No(1)

Remainder when 1212121212....... (up to 300 digits) is divided by 99?