Simple question on average age.sth like a, b, c weighted separately 1st a, b, c ,then a& b, then b &c ,then c & a at last abc, the last weight was 167,then what will be the average weight of the 7 reading?
a)95 b)95.428 c)95.45 d)94

• the reading of abc is=167
  and a,b,c together is=167
  and ab + bc+ ca=2*167
  so 167+167+334= 668
  now 668/7{for avg.}
  =95.42857143
• 10 years agoHelpfull: Yes(10) No(1)
• given a+b+c=167
  now average=a+b+c+ (a+b)+(c+a)+(b+c)+a+b+c/7
  =167*4/7=668/7=95.4
• 10 years agoHelpfull: Yes(4) No(0)
• combined weight of a+b+c=167
  we have to find [a+b+c+(a+b)+(b+c)+(c+a)+a+b+c]/7=(4a+4b+4c)/7
  [4(a+b+c)]/7=(4*167)/7=95.428 is the answer
  
• 10 years agoHelpfull: Yes(3) No(0)
• As a+b+c weight = 167 , so 1st 3 ie. a,b,c total weight 167 and ab+ba+ca is = 2x167 , total = 668 . Avg = 95.425.
• 10 years agoHelpfull: Yes(0) No(0)
• Ans (167*4)/7 = 95.428
• 10 years agoHelpfull: Yes(0) No(0)
• please explain ??????/ the weight abc is 167 right, then how can we find that
• 10 years agoHelpfull: Yes(0) No(0)
• (167*4)/7=95.4
• 10 years agoHelpfull: Yes(0) No(0)