There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:

A. 20
B. 80
C. 100
D. 200

• A has 100 students and B has 80students.
  
  If a is no of students in A and b is no of students in B, then
  
  a-10 = b+10
  a+20 = 2*(b-20)
  
  solving these eqns, we get
  a=100
• 13 years agoHelpfull: Yes(7) No(2)
• B. 80
  
  A has 80 students and B ahs 70 students.
  
  If a is no of students in A and b is no of students in B, then
  
  a= b+10
  a+20 = 2*(b-20)
  
  solving these eqns, we get
  a=80
• 13 years agoHelpfull: Yes(3) No(6)
• answer will be 100.
  dipin chech ur 1st equation
  it shod be like ...
  a-10=b+10
  ................i may wrong but who ever c answer please tell solution
• 13 years agoHelpfull: Yes(2) No(2)
• Let number of students in room A and B be a and b respectively.
  data1: If 10 students are sent from A to B, then the number of students in each room is the same =>(a-10)=(b+10)
  =>a-b=20..................1
  data2:If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B=> a=2 times b i.e.,(a+20)=2(b-20)
  =>2b-a=60..............2
  
  substitute a=b+20 in eq.2=>2b-b-20=60
  =>b=60+40=80.
  
  we know that a-b=20 from eq.1=>a=80+20=100.
  hence, a=100 , b=80.
• 10 years agoHelpfull: Yes(1) No(0)