An engineer undertakes a project to build a 15 km road in 300 days and employeess 45 mens for this. After 100 days he finds that only 2.5 km road has been completed. Find number of extra men he must employ to finish work in time?

a. 43
b. 45
c. 55
d. 68

• 2.5 km road has been completed in 4500 men-days.
  so 1 km has been taken 4500/ 2.5 men-days.
  so remaining 12.5 km would take 4500/2.5* (12.5)= 22500 men days
  
  and remaining days are 200 so men-days / days = men only i.e. 22500/200= 112.5 = 113 men
  so extra required men are 113-45 =68 ans
  
• 9 years agoHelpfull: Yes(28) No(0)
• let x total x worker is required for complete the work
  so 2.5*200:12.5*100::45:x
  x=12.5*100*45/(2.5*200)
  x=112.5
  extra men=112.5-45
  67.5=68
• 9 years agoHelpfull: Yes(16) No(8)
• Work remaining: 12.5km construction.
  Previous condition: 100 days, 45 men, 2.5 km work
  Present condition: 200 days, 45+m men, 12.5 km work.
  
  If work has become 5 times, no of days will be 5 times, i.e., 5x100.
  If men increased from 45 to 45+m days will decrease by the same factor.
  
  Therefore, 5 x 100 x 45/(45+m) =200.
  Ans. 67.5
• 9 years agoHelpfull: Yes(9) No(1)
• Answer: 68
  
  
  45 men working for 100 days -->4500 man-days
  4500 man-days resulted in 2.5 km completion
  therefore rest 12.5 work will require 4500 x 5 man-days(By unitary method)
  This has to be completed in 200 days so number of men required=(4500 x 5)/200 =113(approx)
  
  as already 45 men are working , number of extra men required = (113-45)= 68(ans)
• 9 years agoHelpfull: Yes(8) No(0)
• ans. 68
  let the no. of extra men be x.
  2.5/15=1/6
  so, a/q
  45*100/1/6=(45+x)*200/5/6
  x=67.5=68
• 9 years agoHelpfull: Yes(7) No(2)
• the ans will be (2) because they are 45mens and completed 2.5km road in 100 days if he add 45 more men than 90 men will finish the work in 300days
• 9 years agoHelpfull: Yes(7) No(3)
• (M1 * D1)/W1 = (M2 * D2)/W2
  (45 * 100)/2.5 = ((45+X) * 200)/12.5
  By solving above we get extra men x = 67.5 = 68
• 9 years agoHelpfull: Yes(7) No(0)
• 45 men completes 2.5 km of road in 100 days ,
  so if ,for the time being we consider 45 more men is needed for the task completion within the deadline then, 90(45 + 45) men completes 5 km of the road in 100 days so, 15 km of the road would be completed in 300 days, hence the answer is 45.
• 9 years agoHelpfull: Yes(2) No(8)
• BY Direct formula :M1D1W2=M2D2W1
  45 men prepare 2.5 km in 100 days
  then how many more men are needed to prepare 15-2.5=12.5km in 300-100=200 days
  Now by the formula 45*100*12.5=x*200*2.5
  x=112.5=113 approx
  required no of persons to be added=113-45=68
  
• 9 years agoHelpfull: Yes(2) No(0)
• ans. 45
  100 days are needed to complete 2.5 kms. So, in 300 days we can complete 7.5 kms which is just half of the desired road. So we need double amount of people to complete the work within 300 days. i.e. 45*2=90 men which is 45 more than the former scenario
• 9 years agoHelpfull: Yes(1) No(6)
• 2.5 km in 100day by 45 man
  so 1 man in 1 day 2.5/(100*45)
  for next 12.5 km in 200 day =12.5/(2.5*2/45)
  = 112.5=113
  now 113-45=68 ans
  
• 9 years agoHelpfull: Yes(1) No(0)
• 15 days*300 employees= 4500 Man hours =1/6th work( 2.5/15)
  hence total work is 27000 man hours
  
  (45+x)*200 = 5/6( remaining)* 27000
  45+x= 22500/200
  45+x = 113
  x = 68
  option d
• 9 years agoHelpfull: Yes(1) No(0)
• given time 300 days for 15km
  to build 1 km =300/15=20 days
  in 100 days need to build=100/20=5km
  but
  45 men built only 2.5 km road ,for that still 45 men required
• 9 years agoHelpfull: Yes(0) No(1)
• work is always inversely propositional
  
  2.5*300*45 / 15*100*x
  
  22.5
  
  22.5+45=67.5 = 68
• 9 years agoHelpfull: Yes(0) No(0)
• 2.5 is the 1/6 of 15 so
  100 100 100
  1/6 1/6 1/6 = 3/6
  so extra men will do 1 - 3/6 =3/6 in 200 days
  let extra men 45 so in 200 days they will do 2/6 den we have 1/6 work lefft which will be done in 200 days that will be done by 45/2 men i.e. 22.5 men as 45 men do the same work 1/6 work in 100 days so in 200 days half of 45 men required
  so total men required is 45+22.5= 67.5 i.e 68 men
• 9 years agoHelpfull: Yes(0) No(0)