Elitmus
Exam
Logical Reasoning
Cryptography
solve this crypto multiplication.
EJM
DIN
-------------
MJAN
SIAS*
ISSA**
--------------
IIKSMN
Read Solution (Total 12)
-
- first line
EJM * N = MJAN
M *N = N
(1,3,7,9)*5 = 5
6 *(2,4,8)=(2,4,8)
take N= 5
M cannot be 1.
take M = 3
then , EJ3 * 5 = 3JA5
we know to get above 3000 when 5 is one multiple
EJ3 should be 6J3 * 5 or 7J3 *5
take E=6,
6J3 * 5 = 3JA5
if we put J=0, we get 603 * 5 =3015
therefore
m=3
j=0
a=1
n=5
e=6
also second line now
603 * I = SIAS
starting with S and ending with S can only happen if
I=4
603 *4 = 2412
S=2
I=4
Third line
603 * D = ISSA
= 4221
therfore, D=7
603
* 745
_________
3015
2412*
4221**
___________
449235
K=9 - 10 years agoHelpfull: Yes(12) No(1)
- ______6 0 3
____* 7 4 5
----------------
____3 0 1 5
__2 4 1 2 *
4 2 2 1 * *
-----------------
4 4 9 2 3 5 - 10 years agoHelpfull: Yes(10) No(0)
- 603*745=449235
Without hint also we can solve this - 10 years agoHelpfull: Yes(3) No(2)
- 603
* 745
3015
2412
4221
449235 - 10 years agoHelpfull: Yes(2) No(0)
- HERE HINTS N=5 .
- 10 years agoHelpfull: Yes(0) No(0)
- Ans: 449235
j=0, a=1, s=2, m=3, i=4, n=5, e=6, d=7, k=9 - 10 years agoHelpfull: Yes(0) No(0)
- how this 7 4 5 came?..can anyone explain plssss
- 10 years agoHelpfull: Yes(0) No(0)
- can anyboby explain this
- 10 years agoHelpfull: Yes(0) No(0)
- 603
* 745
_________
3015
2412*
4221**
___________
449235 - 10 years agoHelpfull: Yes(0) No(0)
- 6 0 3
7 4 5
----------------------
3 0 1 5
2 4 1 2 *
4 2 2 1 * *
-----------------------------
4 4 9 2 3 5 - 10 years agoHelpfull: Yes(0) No(0)
- 603*745
------------
3015
2412*
4221**
------------
449235
------------- - 10 years agoHelpfull: Yes(0) No(0)
- hints :
I + 0 = I
S+S = I (value of S is : 1 to 4)
Let S= 2 (S+S=I so 2+2=4)
then, I= 4
first line : M*N = N
take M=3
(so value is : 3*5 = 5)
EJM*N=MJAN (603 * 5 = 3015)
second line : M*I=S
we know the value of S= 2 ,M= 3 , I= 4
EJM * I (603 * 4 = 2412)
third line :
EJM*D=ISSA (4221)
603
*745
3015
2412
4221
449235 - 9 years agoHelpfull: Yes(0) No(0)
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