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a semicircle is drawn with AB as it diameter.From c a point on AB
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- ADC for a right angled triangle.
Hence,
AD= sqrt (40)
Angle subtended by the diameter at any point on the circumference of the circle is always 90 degrees i.e. Triangle ABD is a right angles triangle.
Triangle ADC and Triangle ADB are similar triangles.
AD/AC= AB/AD
Hence AB= 20cm
Area of semi-circle ={ pi * (r^2)}/2 = 50pi
- 9 years agoHelpfull: Yes(7) No(0)
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