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Numerical Ability
Permutation and Combination
In how many ways can we put 9 balls in 3 bags so that each bag contain atleast 2 balls each?
Read Solution (Total 9)
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- The correct answer is 10. First lets keep two balls in each bag so we are now left with 3 balls.... the no ways in which three balls can be placed in three bags so that any bag can get any number of balls is 5C2=10....
NOTE: The number of ways in which n things(balls) can be given to r things(bags) or persons such that any person can get any number of things(balls) is (n+r-1)c(r-1) - 10 years agoHelpfull: Yes(26) No(1)
- 3 3 3
2 3 4
2 4 3
3 2 4
3 4 2
4 2 3
4 3 2
2 2 5
2 5 2
5 2 2
so totally 10 ways
- 9 years agoHelpfull: Yes(5) No(0)
- ans: 3*(9C2 + 9C3 +9C4 + 9C5)
Since atlest 2 balls must be there in other two bags hence we will not add 9C6+9C7+9C8+9C9. - 10 years agoHelpfull: Yes(2) No(4)
- Correct answer should be 18.
3c2*6c1= 18 - 10 years agoHelpfull: Yes(2) No(0)
- i gt 10 as ans
- 10 years agoHelpfull: Yes(1) No(0)
- what is the correct answer???
- 10 years agoHelpfull: Yes(1) No(1)
- i got the result and interview is on 27/10 at 11 am
- 10 years agoHelpfull: Yes(0) No(1)
- does only selected candidate get the mail?
- 10 years agoHelpfull: Yes(0) No(0)
- i think 24 ways.. can any one tell the correct ans
- 10 years agoHelpfull: Yes(0) No(2)
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