x^4+4 is not divisble by;-
a). (x+1)^2 + 3
b). (x-1)^2 +1
c). (x-3)^2 + 4
d).none of these

• Substitute the value of x and check if it is divisible using options
  
  Eg: Let x=2 (X^4)+4 = 20
  
  a) (2+1)^2+3 = 12
  20 is not divisible
  
  b) (2-1)^2+1 = 1
  20 is divisible by 1
  
  c) (2-3)^2+4 = 5
  20 is divisible by 5
  
  Hence the option is A
• 9 years agoHelpfull: Yes(14) No(1)
• i think a
  
• 9 years agoHelpfull: Yes(5) No(1)
• option c) i have written i dont knw wheather it is right or wrong
• 9 years agoHelpfull: Yes(0) No(3)
• options are wrong they are like
  a) i dont remember exactly
  b) (x+1)^2 +1
  c) (x-1)^2 +1
  d)none
  a might be the right ans
• 9 years agoHelpfull: Yes(0) No(0)
• i think a and c both any idea how c is divisible
• 9 years agoHelpfull: Yes(0) No(0)
• (x^4)+2^2 = (x^2)2+2^2
  take x^2 =a , 2=b
  => a2+b2 =(a+b)2-2ab =>( x2+2)^2-2(2)x2 =>
  it is in the form of a2-b2 => (a+b)(a-b)
  (x2+2+2x)(x2+2-2x) .
  it is divisible by only option b.
  => the question is wrong.
  
• 9 years agoHelpfull: Yes(0) No(0)