The total number of pupils in three classes of a school is 333. The number of pupils in classes I and II are in the ratio 3 : 5 and those in classes II and III are in the ratio 7: 11. Find the number of pupils in the class that had the highest number of pupils.

• class III has highest students = 165.
  classes I:II =3:5 .........(1)
  classes II: III =7:11........(2)
  in above two ratios class II is common. so
  we multiply equ1 with 7 and equ2 with 5 then
  classes I : II=21:35
  classes II : III=35:55
  ratio of three classes is 21:35:55
  we need highest students of class (333*55)/(21+35+55)=165
  
  
• 10 years agoHelpfull: Yes(23) No(1)
• The answer is III class the number of pupils is 165...
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• in class 2 ..i,e - 208.15
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• let the no of students be x,y,z;
  x+y+z=333;
  x/y=3/5; and y/z=7/11;
  y=5x/3 and z=11y/7=11*5x/7=55x/7;
  putting in above eqn
  x+5x/3+55x/7=333 and x=63;y=105 and z=165;
  
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• 165 will be the ans...
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• the class is III
  I:II:III=21:35:55
  I=(21/111)*333=63
  II=(35/111)*333=105
  III=(55/111)*333=165
• 10 years agoHelpfull: Yes(0) No(0)
• 1+2+3=333
  1:2=3:5 2:3=7:11 to equalize 2 multiply 7 with 1:2 and 5 with 2:3
  1:2:3=21:35:55
  111-333
  55-? 333*55/111=165
• 7 years agoHelpfull: Yes(0) No(0)