there r 9 balls and r placed in 3 boxes such that there should be atleast 2 balls in each box find the no of ways

• following combination of balls is possible:
  1). 2,2,5 which can be arranged in 3!/2! ways.
  2) .2,3,4 which can be arranged in 3! ways.
  3). 3,3,3
  so total no of ways=3!/2!+3!+1=10 ways.
• 10 years agoHelpfull: Yes(37) No(2)
• first place 2 balls in each boxes
  so, remaining 3 balls placed in (3+3-1)C(3-1) way =10
• 10 years agoHelpfull: Yes(14) No(1)
• 10 ways....
  
  2,2,5
  2,5,2
  5,2,2
  2,3,4
  2,4,3
  4,2,3
  4,3,2
  3,2,4
  3,4,2
  3,3,3
  
  
• 10 years agoHelpfull: Yes(13) No(2)
• according to question 2 balls in each so 6 ball out of the 9 balls.
  now reaming 3 ball can placed in any box so for that no of ways is :-
  3+3-1c3-1 =5c2 = 10 ways.
• 9 years agoHelpfull: Yes(5) No(0)
• First take 6 balls and put two in each box, So no of ways=1
  remaining Three can be placed in any pattern i.e can be zero in one or two boxes.
  No. of ways=1*(3+3-1C3-1)=5C3=10 ways (Using formula n+r-1Cr-1).
• 9 years agoHelpfull: Yes(3) No(0)
• there are 9 balls .. and in three box each contain atleast 2 balls means minimum total no. of ball required=6 and so selection of balls contain 6,7,8,9 balls.
  for 6 balls.....
  2,2,2
  for 7 balls......
  2,2,3
  2,3,2
  3,2,2
  for 8 balls.....
  2,2,4
  2,4,2
  4,2,2
  2,3,3
  3,2,3
  3,3,2
  for 9 balls.......
  2,2,5
  2,5,2
  5,2,2
  2,3,4
  2,4,3
  4,2,3
  3,2,4
  3,4,2
  4,3,2
  3,3,3
  so total no. of possible ways=20
• 10 years agoHelpfull: Yes(2) No(18)
• first we put 2 balls in each box.
  now we have 3 balls. we can put balls in 3 boxes any box can get any no. of balls.
  1st can put in 3ways in same way we can put 3 balls in 3 box=3*3*3=27
• 10 years agoHelpfull: Yes(2) No(5)
• firstly put 2 ball in each...2+2+2=6.......(because atleast 2 ball in each)
  now remaining ball we have 3 so we can put these 3 ball in 3^3 way
  i.e....3*3*3=27
  total ways=1+27=28
• 10 years agoHelpfull: Yes(2) No(2)
• ans:- 288
  
  no of ways of placing 2 or more balls in three boxes=4!*3!*2!=288
  
  
• 9 years agoHelpfull: Yes(0) No(3)
• 5c3 ways we can do arrange
• 9 years agoHelpfull: Yes(0) No(0)
• first of all put 2 balls in each box so total ball in the box is 6 and the ball left is 3.Now distribute balls in these box in such a way that any box can get any no. of balls which is given by formula (n+r-1)C(r-1) where n=3 becoz 3 balls left and r=3 ,no. of boxes .so by putting these value we get
  5C2=10
• 5 years agoHelpfull: Yes(0) No(0)