. The sum of three digits a number is 17. The sum of square of the digits is 109. If we substract 495 from the number, the number is reversed. Find the number.

• Let the number be abc.
  Then a + b + c= 17 .....(1)
  a2+b2+c2=109 .....(2)
  100a+10b+c -495 = 100c+10b+a ......(3)
  From 3, we get a - c = 5
  So the possibilities for (a, c, b) are (6,1,10), (7,2,8), (8,3,6), (9,4,4)
  From the above, (8,3,6) satisfies the condition.
• 10 years agoHelpfull: Yes(11) No(6)
• 863
  By trail and error method.
• 10 years agoHelpfull: Yes(4) No(0)
• ans is 863
• 10 years agoHelpfull: Yes(2) No(0)
• Can anyone explain me how this happened:
  "So the possibilities for (a, c, b) are (6,1,10), (7,2,8), (8,3,6), (9,4,4)"
• 10 years agoHelpfull: Yes(0) No(0)
• this question check from option 495-109=386
  and reversed (8,3,6) is the only ans which is given
• 10 years agoHelpfull: Yes(0) No(0)
• Hi Sandeep 8,3,6 does not satisfy the last condition because 836-495= 341 when we reverse it we cant get 638
  
  but when 944-495=449
  here reversed so 9,4,4 is the right answer
• 10 years agoHelpfull: Yes(0) No(3)