The rate of failure in an examination is 39.25%. Find the least number of total candidates appeared in the examination.

• if 100 student appear then failure=39.25 ......... which is not possible because number of student can not be fraction,like wise in 200 student,failure=78.5, so we have to make the failure percentage into a unit digit failure not fraction...so min no of student =400 so that no of failure=157..........so least no of student appeared in the exam= 400.
• 10 years agoHelpfull: Yes(14) No(1)
• 39.25(out of 100 appeared) becomes integer value when multiplied by 4, 8, 12....
  The least value is 4
  Total appeared = 100*4 = 400
• 10 years agoHelpfull: Yes(5) No(0)
• Gn. 39.25% rate of failure is there.
  assume 10000 appeared, then 3925 failed
  then, if 2000 appeared,then 785 failed// dividing by 5
  then if, 400 appeared, then 157 failed // dividing by 5
  after this 157/400 ratio wont produce whole no. fraction.
  thus the required answer is 400.
• 10 years agoHelpfull: Yes(3) No(1)
• We have to take care of the number should not be in fraction... As there is .25 in the last part of the digit so if we multiply it by 4 then it will become .25x4=1.00... So here we can see we can eliminate the fraction part by multiplying it with 4. So in 100 people 39.25% student has failed... So we can easily say that the least number of candidates will be 4x100= 400
• 10 years agoHelpfull: Yes(1) No(1)
• 39.25(out of 100 appeared) becomes integer value when multiplied by 4, 8, 12....
  The least value is 4
  Total appeared = 100*4 = 400
  
• 10 years agoHelpfull: Yes(0) No(0)