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In an examination the number of successful students was 4 times the numbr of unsuccessful students If there were 35 less students nd the numbr of unsuccessful students were 9 more,then the ratio of their numbr would have been 2:1 . Find the total numbr of students
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- successful students 4x,unsuccessful student x.total 5x
now,total students become 5x-35 & unsuccessful students x+9 then successful students 4x-44
ratio 4x-44 / x+9=2 / 1
x=31 then total student 5x=155 - 10 years agoHelpfull: Yes(16) No(0)
- X= 4 Y-------1
X-35= 2(y+9) ----2
From 1 and 2 we get
X= 106, Y = 26.5
Total =106+26.5 = 132.5(133) - 10 years agoHelpfull: Yes(0) No(18)
- the ans is- 135
- 10 years agoHelpfull: Yes(0) No(6)
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