A person meets a train at a railway station coming daily at a particular time.One day he is late by 25 minute, and he meet the train 5 km before the station.If his speed is 12 kmph,
what is the speed of the train.

• relative speed=5/(25/60)
  hence relative speed =5*60/25=12kmph
  
  speed of the train -speed of the man=relative speed
  x-12=12->x=24kmph(x is the speed of the train)
• 9 years agoHelpfull: Yes(9) No(1)
• In 25 minutes train travels a distance of 5 km....
  1 hr=60 min
  x hr=25 min
  x=5/12hr
  speed=distance/time
  speed=5/(5/12)
  speed=12km/hr
• 9 years agoHelpfull: Yes(7) No(2)
• if the person comes late then he never meet the train before station ,either he comes earlier or meets the train aftre 5 km.
• 10 years agoHelpfull: Yes(5) No(3)
• 24kmph=speed of train
• 10 years agoHelpfull: Yes(4) No(4)
• Ques. man 25 minute late hai , to train 5 km pahle mil rhi hai , eska matlb train 25 minute me 5 km chal rhi h , so
  chal= duri/ samay
  { duri= 5 km, samay= 25 minute (25/60 hour)
  chal= 5*60/25
  =12 kmph
  
• 9 years agoHelpfull: Yes(4) No(0)
• 25 min=5/12 hr
  speed1=dist/time=5/(5/12)=12kmph
  both train and man are in same direction so,speed of the train=speed1+speed of man=12+12=24 kmph
• 9 years agoHelpfull: Yes(3) No(0)
• Speed of train =13km/h
• 10 years agoHelpfull: Yes(0) No(7)
• plz explain clearly answer
• 10 years agoHelpfull: Yes(0) No(1)
• I think it would be 12kmph. we can check it by back calculation.
  if the speed is 12kmph then in 5mins the train will be able to cover the distance of 5km.
• 10 years agoHelpfull: Yes(0) No(4)
• what is the coorect ans?
• 6 years agoHelpfull: Yes(0) No(1)