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Numerical Ability
Profit and Loss
27. A hawker purchased oranges at the rate of 4 oranges in a rupee, but he sells at the rate of 5 oranges in a rupee. His loss is:
(a) 20%
(b) 25%
(c) 50%
(d) 100%
Read Solution (Total 11)
-
- loss percentage =
((buying price - selling price)/buying price)*100
so it is 20% - 10 years agoHelpfull: Yes(10) No(9)
- cp of 4 oranges= Rs. 1
sp of 5 oranges = Rs, 1
SP of 1 orange = 1/5 = 0.2 rupee
SP of 4 oranges = 4 * 0.2 = 0.8 rupee
% loss = [(CP - SP)/CP]*100
= [(1-0.8)/0.8]*100
= [0.2/0.8]*100
= [1/4]*/100
=25% - 9 years agoHelpfull: Yes(8) No(11)
- loss%=[(cp-sp)/cp]*100
=[(1/4-1/5)/1/4]100
=(1/20)*4*100=20% - 8 years agoHelpfull: Yes(7) No(1)
- loss=(1/4-1/5)/(1/4)*100=20%
- 9 years agoHelpfull: Yes(6) No(4)
- Let cost price of 4 oranges= Rs.100, cost[price of 1 orange is =25
Let selling price of 5 oranges =Rs.100, selling price of 1 orange is = 20
s0, Loss= (Cost price of 1 Orange - Selling price of 1 orange)=25-20=5
Loss %= (loss/c.p of 1 orange)*100
=(5/25)*100= 20% - 8 years agoHelpfull: Yes(6) No(2)
- Option a)20%
C.p of 4 org ---1/-
S.p of 5 org---1/-
Find c.p of 4org
4x= 5(1)
C.p of 4 org is (x)=0.8
Loss = (1-0.8)/1*100 =20%
- 10 years agoHelpfull: Yes(4) No(2)
- 20%
loss percentage =
((buying price - selling price)/buying price)*100
- 10 years agoHelpfull: Yes(1) No(0)
- 400 oranges buys for 100 rupees(4 per rupee) and 400 oranges sells for 80 rupees(400/5=80)
100-80=20
ans=20% - 8 years agoHelpfull: Yes(1) No(2)
- loss =(25/125)*100=20
- 7 years agoHelpfull: Yes(1) No(0)
- 4c.p=5s.p
s.p/c.p=4/5
loss=1
%=1/5*100=20% - 7 years agoHelpfull: Yes(0) No(1)
- 1 rupee = 4 oranges = 25 paisa each
Then for 5 oranges - 20 paisa each
So loss 25-20 = 5 paisa per orange
5/25 * 100 = 20℅ - 7 years agoHelpfull: Yes(0) No(0)
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