Accenture Company Numerical Ability Arithmetic

Question: If 2x = 3y = 6-z then Prove that 1/x + 1/y + 1/z=0
Solution:
2x = 6 -z Þ 2 = 6-z/x -------------(i)
3y = 6 -z Þ 3 = 6-z/y -------------(ii)
Multiplying (i)and(ii)
2x3 = 6-z/x x 6-z/y
61 = 6-z/x +-z/y
Þ1 = (-z/x) +(-z/y)
Þ1= -z(1/x +1/y)
Þ1/-z = 1/x +1/y
Þ 1/x + 1/y + 1/z = 0

Read Solution (Total 2)

2x = 6 -z Þ 2 = 6-z/x -------------(i)
3y = 6 -z Þ 3 = 6-z/y -------------(ii)
Multiplying (i)and(ii)
2x3 = 6-z/x x 6-z/y
61 = 6-z/x +-z/y
Þ1 = (-z/x) +(-z/y)
Þ1= -z(1/x +1/y)
Þ1/-z = 1/x +1/y
Þ 1/x + 1/y + 1/z = 0
9 years agoHelpfull: Yes(0) No(3)

The question is
2^x =3^y = 6^(-z)
Prove that
1/X + 1/y + 1/z = 0
2 years agoHelpfull: Yes(0) No(0)

Accenture Other Question

Is the Recruitment Drive going to take place in Kolkata or it has already taken place? Please let me know if you know any specific dates. In a certain code, the symbol for 0 (zero) is * and that for 1 is $. The numbers greater than 1 are to be
written only by using the two symbols given above. The value of the symbol for 1 doubles itself every
time it shifts one place to the left. (For example, 4 is written as $**; and; 3 is written as $$)

Qn: 60 / 17 can also be represented as:

1] $$$*$*** / $$**$$
2] $$$***** / $$**$$
3] $*$$*$** / $$**$$
4] $$*$*$** / $$**$$