IBM
Company
Logical Reasoning
Number Series
1,1,4,8,14,42,_
a)84,b)57,c)51,d)48
Read Solution (Total 8)
-
- (1*1)=1,1+3=4
(4*2)=8,8+6=14
(14*3)=42,42+9=51
means every time multiply with 1,2,3 then add by 3,6,9 respectively - 10 years agoHelpfull: Yes(45) No(0)
- answer must be 51...
make it pair (1,1),(4,8),(14,48),(51,204)
(1+0,1*1=1),
(1+3=4,4*2=8),
(8+6=14,14*3=42),
(42+9=51,51*4=204 - 10 years agoHelpfull: Yes(17) No(3)
- 1 1 4 8 14 42 51
*1 +3 *2 +6 *3 +9 - 10 years agoHelpfull: Yes(2) No(0)
- (1,1)(4,8)(14,42) 51
1*1=1
1+3*1=4
4*2=8
8+3*2=14
14*3=42
42+3*3=51 - 10 years agoHelpfull: Yes(2) No(0)
- multiply each terms with the factor 3/5 n u"ll get d answr..
- 10 years agoHelpfull: Yes(0) No(1)
- multiply with 1,2,3 and add 3,6,9
so the answer is 51 - 9 years agoHelpfull: Yes(0) No(0)
- ans is 51
diff b/w 2 nd & 3 rd term is 3
diff b/w 4 th & 5 th term is 6
like wise diff b/w 6 th & 7 th is 9
so 42+9=51 - 9 years agoHelpfull: Yes(0) No(1)
- 1*1=1, 1+3=4
4*2=8, 8+6=14
14*3=42, 42+9=51
So answer is 51. - 9 years agoHelpfull: Yes(0) No(0)
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