A man sold two cows for Rs. 210 at a total profit of 5 %. He sold one cow at a loss of 10% and another at a profit of 10%. What is the price of each cow?

• 50 and 150
  after profit, price is 210
  so cost price of 2 cows = 200
  x+y=200
  selling price of 2 cows =210
  0.9x + 1.1y =210 //1 cow sold at 10 % loss and another is at 10% profit
  solving both equations x=50 and y=150
• 10 years agoHelpfull: Yes(20) No(0)
• 50 and 150
  after profit, price is 210
  so cost price of 2 cows = 200
  x+y=200
  selling price of 2 cows =210
  0.9x + 1.1y =210 //1 cow sold at 10 % loss and another is at 10% profit
  solving both equations x=50 and y=150
• 10 years agoHelpfull: Yes(2) No(2)
• 50 and 150
  after profit, price is 210
  so we calculate cost price follows
  (210*5)/100 which is approx 200
  so now cost price is 200
  x+y=200---> (1)
  
  now make another equation
  take the selling price of cows- 210
  and cost price is 200
  so profit is rs10
  from this rs10 there is 10% profit for 1 cow and 10% profit for other cow
  so calculate each loss and profit
  loss- (10*10)/100=1
  loss%= ((10-1)*10)/100= 0.9
  same way finf profit %
  profit- (10*10)/100=1
  loss%= ((10+1)*10)/100= 1.1
  and now make the equation
  0.9x+1.1y=210
  solving both equations we get
  x=50 and y=150
• 9 years agoHelpfull: Yes(1) No(0)
• 50 and 150
• 11 years agoHelpfull: Yes(0) No(5)
• 50and 150
  
• 9 years agoHelpfull: Yes(0) No(2)
• CP=200,suppose one part is X and second is 200-X.
  one part wii sell at 0.9X and other at 1.1(200-X).
  then 0.9X+1.1(200-X)=210 ....
  so x=50 and other is 150
• 9 years agoHelpfull: Yes(0) No(0)