Infosys
Company
Logical Reasoning
Cryptography
2 men r playing tossing a coin. if one of them wins he gets 1$ frm the loser. at the end of a no. of games one of them had 3$ and the other won 3 times. how many games did they play?
Read Solution (Total 2)
-
- Total 9 games.
if one has 3$ = 3 games
if other won 3 times = 3games
on winning three games the first one has to give 3$ to other which means as the first one has 3$ he has won three more games= 3 games
total game won by first= 6
total game won by 2nd =3
hence total game played = 6+3=9
hence 9 games is the ans
- 10 years agoHelpfull: Yes(8) No(0)
- clearly who won the match he get 1$ . Other person won three times so there was three games .But 1 persom had 3$, we don't know either the 3$ were he had intially or not? .
- 10 years agoHelpfull: Yes(0) No(0)
Infosys Other Question