The upper and lower part radius of a bucket is 30 cm. and 20 cm. Its height is 60 cm. How much water can be filled in the bucket ?
It is given that -: 1 litre = 1000 cm.^3

• volume of a frustum- (pi h)/3 (r^2+rR+R^2) h-hight, r-radius of small circle, R-radius of greater circle.
  i.e. volume of the bucket- pi 60/3 (20^2 + 20x30 + 30^2) = pi 38 ltr.
• 10 years agoHelpfull: Yes(20) No(1)
• It,s a special case of frustum of a cone. Please follow the link http://jwilson.coe.uga.edu/emt725/Frustum/Frustum.cone.html
  so on applying the formula as given in the link , solution can be determined.
• 10 years agoHelpfull: Yes(3) No(2)
• capacity ot bucket ={(pi*h)/3}*(R^2 + r^2 + Rr) cm^3
  
• 9 years agoHelpfull: Yes(3) No(0)
• surface area of cylinder=2*pi*(r1-r2)*h+2*pi*(r1-r2)^2
  =1400*pi(ans)
  
• 10 years agoHelpfull: Yes(2) No(4)
• Ans: 119.32 L
• 9 years agoHelpfull: Yes(1) No(0)