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A and B play a game of dice between them. The dice consist of colors on their faces (instead of numbers). When the dice are thrown, A wins if both show the same color; otherwise B wins. One die has 4 red face and 2 blue faces. How many red and blue faces should the other die have if the both players have the same chances of winning?
option
a) 3 red and 3 blue faces
b) 2 red and remaining blue
c) 6 red and 0 blue
d) 4 red and remaining blue
Read Solution (Total 10)
-
- ANS is 3 red and 3 blue faces
Let 2 dice contains x no of red faces and y no of blue faces
probability of winning A=(4/6)*(x/6)+(2/6)*(y/6)
probability of winning B=(2/6)*(x/6)+(4/6)*(y/6)
both probabilities are equal according to the given condition
therfore 4x+2y=2x+4y
x=y
hence x=3 and y=3 - 14 years agoHelpfull: Yes(151) No(6)
- here, Probability of Winning = Probability of losing = 1/2
So, Probability of both red is 4/6 * x/6 [ where x is the number of red faces on the other die ]
Probability of both blue is 2/6 * (6-x)/6
so
Probability of same color = PRobability of both red OR Probability of both blue
= 4/6 * x/6 + 2/6 * (6-x)/6 = 1/2
4x/36 + (12-2x)/36 = 1/2
12+2x=18
2x = 6
x=3
So red=3 and blue=3 - 14 years agoHelpfull: Yes(52) No(2)
- Answer: a
Chances of winning of A = 4/6 * 3/6 + 2/6 * 3/6 = 18/36
Chances of winning of B = 1 - 18/36 = 18/36 - 14 years agoHelpfull: Yes(12) No(5)
- ans is a..
choosing red from 2 boxes is 2/3 and 1/2.
choosing blue from 2 boxes is 1/3 and 1/2.
for A to win,same colors occur.
(2/3)*(1/2)+(1/3)*(1/2)=(1/2)
for B to win,different colors occur.
(2/3)*(1/2)+(1/3)*(1/2)=(1/2) - 14 years agoHelpfull: Yes(5) No(1)
- to get equal chance of winning..the dice must be unbiased....so the second die must contain 4 red and 2 blue faces...so the answer is D
- 14 years agoHelpfull: Yes(4) No(19)
- 2 red and remaining blue
- 14 years agoHelpfull: Yes(2) No(32)
- b) 2 red and remaining blue.
- 14 years agoHelpfull: Yes(2) No(16)
- can anyone plzz tell which is d correct answer..
- 12 years agoHelpfull: Yes(2) No(0)
- For both of them to have an equal chance of winning,
The probability that a single color pops up on the two dice should be half
So, Probability (dice 1 is red AND dice 2 is red) + Probability (dice 1 is blue AND dice 2 is blue) = 1/2
Let the other dice have x red faces
So, it will have 6-x blue faces
So,
(4/6)*(x/6) + (2/6)*(6-x)/6 = 1/2
So, x = 3, y=3 - 11 years agoHelpfull: Yes(1) No(0)
- 4 red 4 blue. as there are 4 red 2 blue sides in dice 1.
- 14 years agoHelpfull: Yes(0) No(9)
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